Formula and method
Floor positions N = ceil(quantity/confirmed layers); floor area A = unit length × unit width × N; LDM = A/usable truck width. Dimensions are in metres. An incomplete final stack still uses a full floor position; do not divide floor area by an average layer count.
Worked example
Ten identical 1.2 × 0.8 m units, one confirmed layer and a 2.4 m truck width need 10 floor positions, 9.6 m² and an area equivalent of 4 LDM.
Assumptions and limits
- Include pallets, packaging, overhang and required footprint in the dimensions. Quantity and layers must be exactly representable positive integers. The default 2.4 m is a common calculation-width example; replace it with the vehicle or carrier convention.
- Layers means the maximum units per stack confirmed by you. This tool does not establish stackability, and multiple units are never assumed to be stackable. The default is one layer.
- The result does not arrange orientation, rows, gaps, securing or vehicle length, and does not check axle load, gross weight, door openings, internal height or handling. Real loading may need more space.
- No freight price, chargeable weight or carrier-approved stacking discount is calculated. Mixed sizes, irregular cargo and packages that cannot be stacked together need separate assessment and carrier confirmation.
Frequently asked questions
How many LDM is one 1.2 × 0.8 m pallet?
With a 2.4 m calculation width and one layer, its area is 0.96 m², equivalent to 0.4 LDM. This does not guarantee a physical 0.4 m loading length; layout and other cargo still matter.
How are five units with two confirmed layers handled?
They need ceil(5/2) = 3 floor positions, not 2.5. The last single unit still needs a full footprint. At 1.2 × 0.8 m per unit and a 2.4 m width, the result is 1.2 LDM.
Does LDM prove that the cargo fits?
No. It converts footprint area into an equivalent full-width length. A loading plan must also check unit dimensions, orientation, vehicle length, gaps, weight, stacking and securing.