Formula and method
Worked example
100 kW, PF 0.75 to 0.95, 400 V, 50 Hz, delta: approximately 55.323 kvar; line current 192.450 A to 151.934 A; 366.874 µF per branch.
Assumptions and limits
- Capacitance is for each of three identical branches, not their sum. For the same voltage, frequency and total kvar, each star branch needs three times the delta capacitance.
- This is a preliminary estimate. Electrical design must verify voltage ratings, harmonics, resonance, reactors, switching steps, protection and motor self-excitation. Do not connect correction capacitors directly to a VFD output.
- Compensation does not change load active power in this model. The current reduction is not a percentage saving in energy or bills; actual savings depend on line losses and tariff terms.
Frequently asked questions
Does 50 Hz versus 60 Hz change the required kvar?
With fixed active power and power factors, required kvar is unchanged. The capacitance needed to supply it is inversely proportional to frequency.
Why not always target 1.00?
Load variation may cause overcompensation and a leading power factor. A target of 1 is an ideal mathematical boundary; practical design depends on the load profile and switching control.