Problemas matemáticos y razonamiento · Simultaneous Equations & Models
Visualizador del problema de gallinas y conejos
Visualizador de los 4 métodos clásicos para el problema de gallinas y conejos enjaulados
- Cálculo en cliente
- Sin registro
- Derivación en vivo
- Modo proyector
- Hoja de trabajo A4
Ventana de demostración matemática● 60 FPS
Variables de control del experimento
animales
pasos
Derivaciones y métricas en tiempo real
Conejos calculados
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Gallinas calculadas
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Patas en el suelo (tras levantar)
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Comprobación
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Derivación de fórmulas en tiempo real
Fórmula básica:
--Sustitución de valores:
--Conclusión: --
Ejemplos clásicos y análisis de errores en exámenes
Worked Problem
Problema: 20 heads and 54 feet. How many chickens and rabbits?
Derivación paso a paso:
- Whistle method: 20 animals lift 2 feet each = 40 lifted. Remaining on ground = 54 - 40 = 14. Rabbits = 14 / 2 = 7. Chickens = 20 - 7 = 13.
Worked Problem
Problema: Trucks have 6 wheels, cars have 4. A parking lot has 18 vehicles and 88 wheels. How many of each?
Derivación paso a paso:
- Assume all 18 are cars = 72 wheels. Deficit = 88 - 72 = 16 wheels. Difference = 6 - 4 = 2 wheels/truck. Trucks = 16/2 = 8. Cars = 18 - 8 = 10.
Hoja de indagación en clase y tareas
Q1. Variant 1: 20-question test: +5 for correct, -2 for incorrect. Student scored 72. How many correct?
Answer Key: Max score = 20*5 = 100. Deficit = 100 - 72 = 28. Cost per wrong answer = 5 - (-2) = 7. Wrong = 28/7 = 4. Correct = 20 - 4 = 16.
Q2. Variant 2: Move 1000 glass vases. Earn $0.50 per safe vase; break one loses fee and pays $5 fine. Paid $456. How many broken?
Answer Key: Ideal earn = 1000 * 0.5 = $500. Shortfall = $500 - $456 = $44. Loss per broken vase = 0.5 + 5 = $5.50. Broken = 44 / 5.5 = 8 vases.
Q3. Variant 3: 40 coins of 10-cent and 50-cent total $12.00. How many of each coin?
Answer Key: Total = 1200 cents. Assume all 40 are 10-cent = 400 cents. Deficit = 800 cents. Difference = 50 - 10 = 40 cents. 50-cent = 800/40 = 20 coins.
Preguntas frecuentes y errores conceptuales
Why do math teachers praise the Whistle Leg-Lift method as the premier intuition builder?
It physically eliminates the 2-legged chickens by having them sit down, collapsing a 2-variable linear system into trivial single-step arithmetic!
What does it mean if calculated animal count is negative or fractional?
The problem inputs are mathematically contradictory! Total feet must be even and strictly bounded between 2*Heads and 4*Heads.
How does the chicken-and-rabbit model map to modern business and computing?
It is the quintessential 2-variable linear programming archetype: fleet sizing, financial asset allocation, and server cluster load balancing.
How does middle-school algebra (systems of linear equations) relate to elementary assumption methods?
Identical! Multiplying x+y=H by 2 and subtracting from 2x+4y=F eliminates x, which is mathematically identical to lifting 2 feet!