Spatial Geometry & Functions · Common Core Grade 8 Geometry (Pythagorean Theorem Applications), GCSE Maths (3D Geodesics & Unfolding), AMC 8/10 Surface Geometry.
Shortest Surface Path & 3D Unfolding Visualizer
Transform complex 3D surface curves into straight 2D lines. Unfold a cylinder into a rectangle where the shortest path is the diagonal √( (2πr)² + h² ), or unfold a cuboid into 3 permutations to minimize Euclidean distance.
- Client-side
- No Sign-up
- Live Derivation
- Projector Mode
- Print Worksheet
3D Simulation Stage● 60 FPS
Parameter Controls
type
cm
cm
cm
laps
Live Derivations & Metrics
min_path_len
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Straight line distance on unfolded net
base_circumference
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2πr × turns for cylinder
cuboid_plan1
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Unfolding front-top face pair
cuboid_plan2
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Unfolding front-right face pair
Real-Time Formula Derivation
Governing Formula:
--Substitution:
--Regime: --
Worked Examples & Exam Question Deep Dive
Cuboid Geodesic: Dimensions 3×4×5, Shortest Path from Corner A to Opposite Corner B
Problem: A cuboid has length 3 cm, width 4 cm, height 5 cm. An ant crawls on the outer surface from bottom corner A to opposite top corner B. Find the shortest path distance.
Analytical Strategy: Three unfolding pairs: (1) Combine length and width: √((3+4)² + 5²) = √74 ≈ 8.60 cm; (2) Combine length and height: √((3+5)² + 4²) = √80 ≈ 8.94 cm; (3) Combine width and height: √((4+5)² + 3²) = √90 ≈ 9.49 cm. Shortest path is √74 cm. General rule: sum the two smallest dimensions!
Step-by-Step Derivation:
- Step 1: Sort dimensions: a=3 < b=4 < c=5.
- Step 2: Unfolding 1: √((3+4)² + 5²) = √74 ≈ 8.60 cm.
- Step 3: Unfolding 2: √((3+5)² + 4²) = √80 ≈ 8.94 cm.
- Step 4: Unfolding 3: √((4+5)² + 3²) = √90 ≈ 9.49 cm.
- Step 5: Compare: minimum is √74 ≈ 8.60 cm.
⚠️ Common Misconception Pitfall: Testing only one unfolding: always compare all 3 permutations or use the golden rule that summing the two smallest dimensions yields the minimal hypotenuse.
Student Inquiry Worksheet & Practice Problems
Q1. Cylinder has circumference 12 cm and height 5 cm. What is the shortest surface path for 1 full turn around the side?
Answer Key: 13 cm (√(12² + 5²) = √169 = 13)
Q2. For a 2×3×4 cuboid, which two side lengths should be added together for the shortest surface path?
Answer Key: 2 and 3 (the two smallest sides: √((2+3)² + 4²) = √41)
Frequently Asked Questions & Misconceptions
Why does a 2-turn spiral on a cylinder correspond to twice the circumference in the unfolded rectangle?
Each full turn traverses one unrolled cylinder width. Two turns are equivalent to tiling two identical rectangles side by side, making the horizontal base exactly 2 × (2πr).