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Electricity & Magnetism · GCSE Physics Topic 4 (Electricity & Power)

Rated vs Actual Power Bulb Brightness Simulator

Key exam takeaway: Bulb brightness depends solely on ACTUAL power dissipation. In series, the 40W bulb has higher resistance (R=U²/P) and glows brighter than the 100W bulb.

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Local Calculation · Private
Interactive Science Laboratory Pure client-side physics and mathematical computation. Inputs are processed locally without personal data storage.
Presets & Common Traps:
3D Simulation Stage● 60 FPS

Parameter Controls

V
W
W

Live Derivations & Metrics

Bulb 1 Actual Power
--
Bulb 2 Actual Power
--
Bulb 1 Resistance R1
--
Bulb 2 Resistance R2
--
Real-Time Formula Derivation
Governing Formula: --
Substitution: --
Regime: --

Worked Examples & Exam Question Deep Dive

Worked Problem

Problem: Bulbs L1 (6V 3W) and L2 (6V 6W) wired in series across 9V. Which lights normally? Does either burn out?
Step-by-Step Derivation:
  1. I1_rated = 0.5A, R1 = 12Ω. I2_rated = 1.0A, R2 = 6Ω. Series current I = 9/(12+6) = 0.5A. L1 operates at rated 0.5A normally; L2 operates dimly; neither burns.

Worked Problem

Problem: An electric meter reads 3000 rev/(kW·h). A kettle alone turns disk 150 rev in 3 min. Find its actual electrical power.
Step-by-Step Derivation:
  1. Energy consumed W = 150/3000 = 0.05 kW·h = 180 kJ. Time t = 180s. Actual power P = W/t = 180,000/180 = 1000W.

Student Inquiry Worksheet & Practice Problems

Q1. Variant 1: Comparing 220V 40W and 220V 100W incandescent bulbs, which filament is thicker?
Q2. Variant 2: In measuring bulb power, can multiple trial wattages be averaged as "rated power"? Why?
Q3. Variant 3: Why do incandescent lightbulbs almost always burn out the instant they are switched on?

Frequently Asked Questions & Misconceptions

Is "kWh" a unit of power or energy? How many Joules is 1 kWh?
Energy! 1 kWh = 1000W * 3600s = 3.6*10^6 Joules (3.6 MJ). It powers a 100W bulb for 10 hours.
Why are LED bulbs far more energy-efficient than incandescent bulbs?
Incandescent bulbs waste >90% of electricity as invisible thermal infrared heat. LEDs generate light via solid-state electroluminescence at >50% efficiency.
To connect two 110V bulbs in series across 220V, what condition must hold?
Their rated wattages must be strictly identical! Otherwise unequal resistances split voltage unequally, overvolting and blowing the higher-resistance bulb.
Do household appliances consume power in standby mode?
Yes! Internal power transformers and microcontrollers remain energized, drawing 0.5W to 5W per device continuously (phantom load).